I found this very difficult to figure out but the answer is Br2(l) is produced at the anode and Ag at the cathode. the rest is all not produced, can someone please explain why the H2 and O2 are also not produced.
Write down all the reductions and oxidations occurring: reduction potentials are in brackets
REDUCTION @ CATHODE
Ag+ + e- ---> Ag (+0.80V)
2H+ + 2e- ---> H2 (+0.00V)
2Na+ + 2e- ---> 2Na (-2.71V)
OXIDATION @ ANODE
2Br- ---> Br2 + 2e- (-1.07V)
2H2O----> O2 + 4H+ + 4e- (-1.23V)
2F- ---> F2 + 2e- (-2.87V)
Only the reaction with the most positive electrode potential will occur at each electrode.. So only Ag(s) and Br2(l) are formed.