29 Jun, 2021 08:09 PM

Solve and check. 1/w^2+2w-8+3/w^2+w-6=1/w^2+7w+12?

Select the correct choice below,and if necessary, fill in the answer box to complete your choice. W= __ (Simplify your answer.Use comma to separate answers as needed.)

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Answer
HA
29 Jun, 2021 08:09 PM

1/(w^2 + 2w - 8) + 3/(w^2 + w - 6) = 1/(w^2 + 7w + 12)

1/((w + 4)(w - 2)) + 3/((w + 3)(w - 2)) = 1/((w + 3)(w + 4))

(w + 3)/((w + 4)(w - 2)(w + 3)) + 3(w + 4)/((w + 4)(w - 2)(w + 3)) = (w - 2)/((w + 4)(w - 2)(w + 3))

(w + 3) + 3(w + 4) = w - 2

w + 3 + 3w + 12 = w - 2

4w + 15 = w - 2

4w - w = -2 - 15

3w = -17

w = -17/3

AV
29 Jun, 2021 08:10 PM










You must be joking. How can anyone interpret this without many many many

 parentheses, and spaces to help separate terms.